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Milwaukee Bucks' Malcolm Brogdon wins NBA's Rookie of the Year award

Team's first RoY since Kareem Abdul-Jabbar in 1970
Milwaukee Bucks' Malcolm Brogdon wins NBA's Rookie of the Year award
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Maddie Meyer
<p>BOSTON, MA - MARCH 29: Malcolm Brogdon #13 of the Milwaukee Bucks drives against Isaiah Thomas #4 of the Boston Celtics during the first quarter at TD Garden on March 29, 2017 in Boston, Massachusetts. NOTE TO USER: User expressly acknowledges and agrees that by downloading and or using this photograph, User is consenting to the terms and conditions of the Getty Images License Agreement. (Photo by Maddie Meyer/Getty Images)</p>
Milwaukee Bucks' Malcolm Brogdon wins NBA's Rookie of the Year award
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Milwaukee Bucks guard Malcolm Brogdon has gone from second round afterthought to NBA Rookie of the Year. Brogdon beat out two Philadelphia 76ers big men Joel Embiid and Dario Saric for the award on Thursday night.

The four-year star out of the University of Virginia averaged 10.2 points and 4.2 assists per game for the Bucks this season, and shot 40.4 percent from beyond the arc.

Brogdon was a do-it-all asset for Milwaukee; he finished in the top five among all rookies in minutes, points, assists, steals, three-point percentage, and free throw percentage.

Brogdon is the first Bucks player to win the award since Kareem Abdul-Jabbar (then Lew Alcindor) in 1970.

Copyright 2016 Scripps Media, Inc. All rights reserved. This material may not be published, broadcast, rewritten, or redistributed.

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